.plzzzz..solve explain it clearly.... Tomorrow is my exams
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parallelogram AEGD equals to parallelogram BEGC ...the midpoints
then triangle ABE is congruent to FCG ..also RDG is congruent to EBF ..
and and when equals are subtracted from equals then remaining are also equal ....
then triangle ABE is congruent to FCG ..also RDG is congruent to EBF ..
and and when equals are subtracted from equals then remaining are also equal ....
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