Question

plzzzz solve the problem

Answer 1

HELLO DEAR,


raidus of circle= OB


AB =4CM

AO =5CM

IN ∆ ABO


<ABO =90°
${ao}^{2} = {ab}^{2} + {ob}^{2} \\ \\ = > {5}^{2} = {4}^{2} + {bo}^{2} \\ \\ = > {bo}^{2} = 25 - 16 \\ \\ = > {bo}^{2} = 9 \\ \\ = > bo = \sqrt{9} \\ \\ = > bo = 3cm$
I HOPE ITS HELP YOU DEAR,
THANKS