Math, asked by albzakirhussain, 1 year ago

Plzzzz solve this...

Attachments:

Answers

Answered by Anonymous
0
m= 1/(3-2√2)

multiply N and D by 3+2√2

3+2√2)/9 -8

3 + 2√2

Now m^2 = 9 + 8 + 12√2 = 17 +12√2

n= 1/(3+2√2)

multiply N and Dby 3-2√2

3-2√2)/ 9 - 8

3-2√2

now n^2 = 9 + 8 -12√2 = 17 -12√2

mn = 1/( 3+2√2)(3-2√2)

= 1/9 -8

= 1/1 = 1
Similar questions