Plzzzz solve this...
Attachments:
Answers
Answered by
0
m= 1/(3-2√2)
multiply N and D by 3+2√2
3+2√2)/9 -8
3 + 2√2
Now m^2 = 9 + 8 + 12√2 = 17 +12√2
n= 1/(3+2√2)
multiply N and Dby 3-2√2
3-2√2)/ 9 - 8
3-2√2
now n^2 = 9 + 8 -12√2 = 17 -12√2
mn = 1/( 3+2√2)(3-2√2)
= 1/9 -8
= 1/1 = 1
multiply N and D by 3+2√2
3+2√2)/9 -8
3 + 2√2
Now m^2 = 9 + 8 + 12√2 = 17 +12√2
n= 1/(3+2√2)
multiply N and Dby 3-2√2
3-2√2)/ 9 - 8
3-2√2
now n^2 = 9 + 8 -12√2 = 17 -12√2
mn = 1/( 3+2√2)(3-2√2)
= 1/9 -8
= 1/1 = 1
Similar questions