Question

the tenth place of a three digit number is zero the sum of a two digit number and the number obtained by interchanging the digit is 1010. find the pair of numbers that is original number and the number obtained by interchanging the digits .is it possible to have more than one such pair? if yes write all the pair.

Answer 1

Answer:

Step-by-step explanation:

let say number = 100x + 10y +z

y = 0

100x +z is the number

number by interchanging digits = 100z +x

100x +z + 100z + x = 1010

101x + 101z = 1010

x+z = 10

pair can be

1,9 ,  109 , 901

2,8  208 802

3,7   307 , 703

4,6   406 , 604

5,5   505 , 505

6,4    604 , 406

7,3 , 703 , 307

8,2   802, 208

9,1   901, 109