Question

plzzzz solve this question....fast..plzzz

Answer 1

angle ACD = angle ABD (angle formed by the same segment)

In ∆ECD,
angle(ECD+EDC+CED) = 180° ( sum of all interior angles of a triangle is 180°)
85° + angle CED = 180°
angle CED = 95°

angle CEB + angle CED = 180° ( linear pair axiom)
angle CEB = 180° - 95° = 85°

angle BAC = angle CDB ( angle formed by the same segment)

In ∆ABD,
angle BAC + angle ABD + angle ADB = 180° ( sum of all interior angles of a triangle is 180°)
angle ADB = 180°-(90°+50°) =40°