Question

plzzzz tell me...............................

Answer 1

Here,

Power,P=10W
Potential difference.V=220V
Current,I=5A
Resistance of each bulb,K=?
W/K

P=V square/K (K is resistance)

K=V square/P

=220 square/10
=48400/10
=4840

so, K=4840 ohm

Now according to ohm law

V=IR

R=V/I
=220/5
=44
Therefore,

R=44 ohm

Let the number of electric bulbs connected parallel to the circuit be x.

Here, Resistance of the circuit,
R=44 ohm

Resistance of each bulb,K=4840 ohm

Therefore,

1/R=1/K*x (* means mutiply)

x=K/R
=4840/44
=110

Hence,a total of 110 lamps can be connected.......... current is 5A