Question

plzzzz zzz solve it............. ​

Answer 1

ANSWER:

Acceleration = Change in velocity/time taken

Acceleration = Change in velocity/time takenIn the first two seconds,

Acceleration = Change in velocity/time takenIn the first two seconds,Acceleration = [(33.6 - 30)/2] km/h2

Acceleration = Change in velocity/time takenIn the first two seconds,Acceleration = [(33.6 - 30)/2] km/h2 = 1.8 km/h2

Acceleration = Change in velocity/time takenIn the first two seconds,Acceleration = [(33.6 - 30)/2] km/h2 = 1.8 km/h2 = 0.5 m/s2 …(i)

Acceleration = Change in velocity/time takenIn the first two seconds,Acceleration = [(33.6 - 30)/2] km/h2 = 1.8 km/h2 = 0.5 m/s2 …(i)In the next two seconds,

Acceleration = Change in velocity/time takenIn the first two seconds,Acceleration = [(33.6 - 30)/2] km/h2 = 1.8 km/h2 = 0.5 m/s2 …(i)In the next two seconds,Acceleration = [(37.2 - 33.6)/2] km/h2

Acceleration = Change in velocity/time takenIn the first two seconds,Acceleration = [(33.6 - 30)/2] km/h2 = 1.8 km/h2 = 0.5 m/s2 …(i)In the next two seconds,Acceleration = [(37.2 - 33.6)/2] km/h2 = 1.8 km/h2

Acceleration = Change in velocity/time takenIn the first two seconds,Acceleration = [(33.6 - 30)/2] km/h2 = 1.8 km/h2 = 0.5 m/s2 …(i)In the next two seconds,Acceleration = [(37.2 - 33.6)/2] km/h2 = 1.8 km/h2 = 0.5 m/s2…(ii)

Acceleration = Change in velocity/time takenIn the first two seconds,Acceleration = [(33.6 - 30)/2] km/h2 = 1.8 km/h2 = 0.5 m/s2 …(i)In the next two seconds,Acceleration = [(37.2 - 33.6)/2] km/h2 = 1.8 km/h2 = 0.5 m/s2…(ii)From (i) and (ii), we can say that the acceleration is uniform.

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Answer 2

Answer:

ans 0.5s, yes................