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angleBEF + angleEFD = 180 (co interior angles)
angleBEG = angleGEF. (given)
angleEFG = angleGFD. (given)
which implies,
angleEGF + angleGEF = 90
Now in triangle EGF,
angle(EGF + GFE + FEG) = 180
angleEGF + 90 = 180
angleEGF = 90
Hence Proved........
angleBEG = angleGEF. (given)
angleEFG = angleGFD. (given)
which implies,
angleEGF + angleGEF = 90
Now in triangle EGF,
angle(EGF + GFE + FEG) = 180
angleEGF + 90 = 180
angleEGF = 90
Hence Proved........
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