Question

plzzzzz answer fastt

Answer 1

(3+√8)^2 + 1/(3+√8)^2
apply (a+b)^2 =a^2+b^2+2ab formula
9+6√8+8 + 1/9+6√8+8
17+6√8 + 1/17+6√8
17+6√8(17+6√8)/17+6√8
289+102√8+48/ 17+6√8
take 17 which is common in numerator
17(17+6√8) / 17+6√8
cancel (17+6√8) from numerator and denominator
17 is the answer