Question

plzzzzz answer in detail

Answer 1

AnswEr :

First Case

Two forces of magnitude 15 N each are acting on a block in opposite directions.

The net force on the object would be :

$\implies \: \sf \: F_{net} = 15 \hat{i} + 15 ( - \hat{i}) \\ \\ \implies \: \sf \: F_{net} = 0 \: N$

Since,

$\sf \sum F_{x} = 0 \: N$

The block will continue to stay in rest.

Second Case

Two forces of magnitude 25 N and 15 N are acting on the object in opposite directions. 25 N along the negative x-axis and 15 N along the positive x - axis.

The net force would be :

$\implies \: \sf \: F_{net} = 15 \hat{i} + 25 ( - \hat{i}) \\ \\ \implies \: \sf \: F_{net} = - 10 \hat{i} \: \: N \\ \\ \implies \: \sf \: | F_{net} | = \sqrt{(-10 \hat{I})^2} = \sqrt{100 \hat{i^2}} = \sqrt{100 \times 1} = 10\: N$

Here,the net force is in the direction of negative x - axis.

The block will move towards the left side.