Question

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Answer 1

5)Mr. Malik saves Rs. 12,500

6)The population after 3 years will be 1,30,000

10) Percentage of:
a) Curd - 50%
b) Water - 30%
c) Sugar syrup - 20%

Answer 2

Answer : (2)

let the population of first year is x

increase 5% = 5x/100

increase in second year = 7% = 7x/100

Given : Second year population is 40446

According to the given question


$\dfrac{5x}{100} + \dfrac{7x}{100} = 40446$


$\dfrac{12x}{100} = 40446$


12x = 4044600


$x = \dfrac{4044600}{12} = 337050$


Hence : population at the beginning was 337050.

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Answer : (5)

Given : per month salary = ₹ 50,000

spending = 75%

savings = 100 - 75 = 25%

Finding his savings -

50,000 x 25/100 = 12,500

So, per month savings = ₹ 12,500

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Answer : (6)

Given : increase = 10%

present population = 1,00,000



First year population -

1,00,000 x 10% = 10,000

1,00,000 + 10,000 = 1,10,000



Second year population -

1,10,000 x 10% = 11,000

1,10,000 + 11,000 = 1,21,000



Third year population -

1,21,000 x 10% = 12,100

1,21,000 + 12,100 = 1,33,100.


Hence : Population after 3 years will be 1,33,100.

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Answer : (10)

Given :

curd = 5 parts

water = 3 parts

sugar = 2 parts .


(A) - percentage of curd = 5/10 x 100 = 50 %


(B) - percentage of water = 3/10 x 100 = 30 %


(C) - percentage of sugar = 2/10 x 100 = 20 %