Rahul sold a watch to Sohan at a gain of 10% and Sohan sold it to Mohan at a loss of 10% If Mohan paid 990 for it , find the price paid by Rahul
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Answered by
42
Solutions :-
Given :
Cost Price for Mohan = Rs 990
Profit for Rahul = 10%
Loss for Sohan = 10%
Let the cost price of watch be x
A/q
=> x (1 + 10%)(1 - 10%) = 990
=> x (1 + 0.1)(1 - 0.1) = 990
=> x × 1.1 × 0.9 = 990
=> 0.99x = 990
=> x = 990/0.99 = 1000
Hence,
The price paid by Rahul is Rs 1000
Given :
Cost Price for Mohan = Rs 990
Profit for Rahul = 10%
Loss for Sohan = 10%
Let the cost price of watch be x
A/q
=> x (1 + 10%)(1 - 10%) = 990
=> x (1 + 0.1)(1 - 0.1) = 990
=> x × 1.1 × 0.9 = 990
=> 0.99x = 990
=> x = 990/0.99 = 1000
Hence,
The price paid by Rahul is Rs 1000
Anonymous:
nice answer bro
Answered by
29
✔️ Given :
C. P for mohan = 990 ₹
Profit for rahul = 10%
Loss for sohan = 10%
Let C. P of watch be x
ATQ
=> x(1 + 10)(1-10)=990
=> x (1 + 0.1)(1 - 0.1)= 990
=> x × 1.1 × 0.9 = 990
=> x = 1000
Therefore, price paid by rahul is 1000
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