Math, asked by qwerty93, 1 year ago

plzzzzz help....in a big hurry!

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Answered by hukam0685
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In a cubic polynomial
sum of zeros=  \frac{ - b}{a} \\ (a + b) + a + (a - b) = \frac{ - 3}{6} \\ 3a = - \frac{1}{2} \\ a = \frac{ - 1}{6} \\ (a + b)a +a (a - b ) + (a + b)(a - b) = \frac{c}{a} \\ {a}^{2} + ab + {a}^{2} - ab + {a}^{2} - {b}^{2} = \frac{ - 5}{6} \\3 {a}^{2} - {b}^{2} = \frac{ - 5}{6} \\ 3 \times \frac{1}{36} - {b}^{2} = - \frac{5}{6} \\ - {b}^{2} = - \frac{5}{6} - \frac{1}{12} \\ {b}^{2} = \frac{10 + 1}{12} \\ {b}^{2} = \frac{11}{12} \\ b = \frac{ \sqrt{11} }{2 \sqrt{3} } \\
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