Math, asked by goose15, 3 months ago

plzzzzz help me out..... ​

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Answers

Answered by BrainlyEmpire
47

\boxed{\rm{\blue{Find \longrightarrow }}}

Velocity After 4 sec

\boxed{\rm{\orange{Given \longrightarrow }}}

Initial velocity [v]= 50cm/sec= 0.5 m/s

Acceleration [a]= 20cm/sec= 0.2 m/s

Time Taken [t] = 4 sec

\boxed{\rm{\pink{Formula \ used \longrightarrow }}}

\sf{ a= \dfrac{v-u}{t}}

where a= acceleration

u= initial velocity

v= final velocity

t= time taken

\boxed{\rm{\red{SoLution \longrightarrow }}}

put value in the formula we get,

\sf{0.2 = \dfrac{v-0.5}{4}}

\sf{ 0.2\times 4 = v - 0.5}

\sf{v=0.8 - 0.5= 0.3m/s}

\underline{\bf{\therefore Velocity\ after\ 4 sec = 0.3m/s}}

__________________________

Answered by BabeHeart
3

\boxed{\rm{\blue{Find \longrightarrow }}}

Velocity After 4 sec

\boxed{\rm{\orange{Given \longrightarrow }}}

Initial velocity [v]= 50cm/sec= 0.5 m/s

Acceleration [a]= 20cm/sec= 0.2 m/s

Time Taken [t] = 4 sec

\boxed{\rm{\red{Formula \ used \longrightarrow }}}

\sf{ a= \dfrac{v-u}{t}}

where a= acceleration

u= initial velocity

v= final velocity

t= time taken

\boxed{\rm{\pink{Solution \longrightarrow }}}

put value in the formula we get,

\sf{0.2 = \dfrac{v-0.5}{4}}

\sf{ 0.2\times 4 = v - 0.5}

\sf{v=0.8 - 0.5= 0.3m/s}

\underline{\bf{\therefore Velocity\ after\ 4 sec = 0.3m/s}}

__________________________

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