Question

plzzzzz solve qstn number 7.....its class 10th icse qstn ​

Answer 1

Answer:

x = 0, 16

Step-by-step explanation:

Given,

x+9, x-6, 4 are terms in a G.P.

When a,b,c are in G.P, then b² = ac.

Now,

(x - 6)² = (x + 9) * 4

⇒ x² + 36 - 12x = 4x + 36

⇒ x² + 36 - 12x - 4x - 36 = 0

⇒ x² - 16x = 0

⇒ x(x - 16) = 0

⇒ x = 0, 16

Hope it helps!