plzzzzz solve this fast... Q.30
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angle QOF=3x+10
But angle QOF=GTP(by corresponding angle)
Hence GTP=3x+10............(1)
Also,
angle TNS=angle GTP=2x+25...........(2)
Now but GTP=TNS
3x+10=2x+25
x=15°
Hence angle TNS= 15+25=40°
But TNS=MNH=40°
mn121:
GTP is not equal to QOF
Answered by
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∠GTP = ∠TNS = 2x + 25 (Corresponding Angles are equal)
∠GTO = 180 - ∠GTP = 180 - (2x+25) = 180 - 2x - 25 = 155-2x (Supplementary angles)
∠FOQ = ∠GTO Corresponding angles)
⇒ 3x+10 = 155-2x
⇒ 3x+2x = 155-10
⇒ 5x = 145
⇒ x =145/5
⇒ x = 29°
∠MNH = ∠TNS (Vertically opposite angles)
= 2x+25 = (2*29)+25 = 58+25 = 83°
hope it helps you...
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