Question

Plzzzzzz answer this question I WILL MARK AS BRAINLIEST

Answer 1

Step-by-step explanation:

mark it brainlist ans now

Answer 2

Step-by-step explanation:

I hope you know that sec²θ-tan²θ=1

secθ+tanθ=m

Then,

LHS=(m²-1)/(m²+1)

=[(secθ+tanθ)²-1]/[(secθ+tanθ)²+1]

=(sec²θ+tan²θ+2secθtanθ-[sec²θ-tan²θ])/(sec²θ+tan²θ+2secθtanθ+[sec²θ-tan²θ])

=(2tan²θ+2secθtanθ)/(2sec²θ+2secθtanθ)

=2tanθ(tanθ+secθ)/2secθ(secθ+tanθ)

=tanθ/secθ

=sinθ=RHS

HENCE VERIFIED