Question

plzzzzzz answrr my question

Answer 1

here is ur answer......

Answer 2

v).
it's multiple (X+1)
so,
$4 \leqslant 3(x + 1) \leqslant 6$
$4 \leqslant 3x + 3 \leqslant 6$
subtraction by 3
$4 - 3 \leqslant 3x + 3 - 3 \leqslant 6 - 3$
$1 \leqslant 3x \leqslant 3$
divide by 3
$1 \div 3 \leqslant x \leqslant 1$