plzzzzzz do question 6 with method
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Answered by
7
3x + 2/3 = 2x + 1
![= > 3x - 2x = 1 - \frac{2}{3} \\ = > x = \frac{3}{3} - \frac{2}{3} \\ = > x = \frac{1}{3} = > 3x - 2x = 1 - \frac{2}{3} \\ = > x = \frac{3}{3} - \frac{2}{3} \\ = > x = \frac{1}{3}](https://tex.z-dn.net/?f=+%3D++%26gt%3B+3x+-+2x+%3D+1+-++%5Cfrac%7B2%7D%7B3%7D++%5C%5C++%3D++%26gt%3B+x+%3D++%5Cfrac%7B3%7D%7B3%7D++-++%5Cfrac%7B2%7D%7B3%7D++%5C%5C++%3D++%26gt%3B+x+%3D++%5Cfrac%7B1%7D%7B3%7D+)
Since 2x is positive in RHS (Right hand side) we make it negative in LHS (Left hand side)
1/3 is your answer
Hope it helps dear friend ☺️
Since 2x is positive in RHS (Right hand side) we make it negative in LHS (Left hand side)
1/3 is your answer
Hope it helps dear friend ☺️
adibuddy:
you have said that maybe you are too bad
Answered by
5
3x+2/3=2X+I
![9x + 2 = 6x + 3 \\ 9x - 6x = 3 - 2 \\ 3x = 1 \\ x = 1 \div 3 9x + 2 = 6x + 3 \\ 9x - 6x = 3 - 2 \\ 3x = 1 \\ x = 1 \div 3](https://tex.z-dn.net/?f=9x+%2B+2++%3D+6x+%2B+3+%5C%5C+9x+-+6x+%3D+3+-+2+%5C%5C+3x+%3D+1+%5C%5C+x+%3D+1+%5Cdiv+3)
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