plzzzzzz give tge answer of thus
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plzzzzzz give the answer very fasttttttttt
plźzozzzzzz because tomoorow us my exam
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There are 56 observations.. And thus the median of positions 3rd and 4th wl b taken.. So
x-2+x/2 = 16
2x-2/2=16
2(x-1)/2=16
x-1=16
x=17
So the other no is 15
So then the mean is
6+7+15+17+17+20/6
= 82/6
=13.6
Answered by
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median=16
total no. of observation=6 which is even
let n=6
median=n/2th +n/2+1th/2
=6/2th+6/2+1th/2
=3th+4th/2
since,third & fourth observation are:x-2 & x
so,x-2+x/2=16
2x-2/2=16
by cross multiplication ;
2x-2=32
2x=34
x=17
now,third observation=x-2=17-2=15
fourth observation=x=17
mean=6+7+15+17+17+20/6
=82/6=13.66(approx)
total no. of observation=6 which is even
let n=6
median=n/2th +n/2+1th/2
=6/2th+6/2+1th/2
=3th+4th/2
since,third & fourth observation are:x-2 & x
so,x-2+x/2=16
2x-2/2=16
by cross multiplication ;
2x-2=32
2x=34
x=17
now,third observation=x-2=17-2=15
fourth observation=x=17
mean=6+7+15+17+17+20/6
=82/6=13.66(approx)
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