Question

plzzzzzz. prove. it. by. mentioning steps

Answer 1

Heya !!!



Tan A + Sec A -1 / Tan A - Sec A +1 = 1+ SinA /Cos A


We have,


LHS = Tan A + Sec A -1 / Tan A - Sec A +1

=> ( Tan A + Sec A ) - ( Sec² A - Tan²A ) / ( Tan A - Sec A +1) [ Sec² theta - Tan²theta = 1 ]



=> ( Tan A + Sec A ) [ 1 -( Sec A - Tan A)] / ( Tan A - Sec A +1)



=> ( Sec A + Tan A ) ( Tan A - Sec A +1) / ( Tan A - Sec A +1)



=> Sec A + Tan A



=> 1/ Cos A + Sin A / CosA



=> ( 1 + Sin A ) / Cos A = RHS



Hence,


LHS = RHS......PROVED......




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