Question

PLZZZZZZZ ANSWER The question in the attachment
with steps..

Answer 1

Answer:

sorry dear I really don't know the answer

Answer 2

$\huge\underline\green {\tt Solution :}$

In the given triangle,

Semiperimeter ( s ) = $\dfrac {a + b + c}{2}$

Area of the triangle = $\sqrt {s (s-a)(s-b)(s-c)}$

In the obtained triangle ( after doubling sides ),

Sides : 2a, 2b and 2c

2S = a + b + c

Area = $\sqrt {2s(2s - 2a)(2s-2b)(2s-2c)}$

= 4 $\sqrt {s (s-a)(s-b)(s-c)}$

Clearly, It is 4 times the area of the given triangle.

So,

It's ratio is 1:4

Now,

Percentage in the increase of area = $\dfrac {Area 2- Area 1 }{Area}$ × 100

= $\dfrac {A- A}{A}$ × 100

= $\dfrac {4A-A}{A}$ × 100

= $\dfrac{3A}{A}$ × 100

= 3 × 100

= 300

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$\huge\mathscr\blue {Be\: Brainly}$