plzzzzzzz help it is Very important for me
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angle BOD=80°.......
indar10:
par angle bodbpucha he nehe
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in cylic quad .inner angle opposite sum is 180
so, ∆bcd=bcd+40=180
bcd=140
in cyclic quad there is a theorem
by this it will be
2∆a=∆bod
so,bod=40°
so, ∆bcd=bcd+40=180
bcd=140
in cyclic quad there is a theorem
by this it will be
2∆a=∆bod
so,bod=40°
ans is wrong
how
what you have to find
bod and bcd
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