Question

plzzzzzzz...............
solve the problem ............
$\sqrt{ - 16 } + 3 \sqrt{ - 25} + \sqrt{ - 36} - \sqrt{ - 625 }$
solve the problem by method of complex number..........
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Answer 1

Answer:

4i+3i+6i-25i = 0 okay take the numbers out of root and then( i) comes from root of -1

Answer 2

Answer:

0

Step-by-step explanation:

$i = \sqrt[]{ - 1}$

Therefore,

$\sqrt{ - 16} = 4i \\ \sqrt[]{ - 25} = 5i \\ \sqrt[]{ - 36} = 6i \\ \sqrt[]{ - 625} = 25i$

Hence, substituting in the above equation,

4i + 3×5i + 6i - 25 i = 0

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Hope it helps...!

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