Question

plzzzzzzzz help its urgent........solve both and I will mark you as brainliest........but the true answer I need​

Answer 1

Answer:

1. 1st number answer is option 2means(4m/s)

Answer 2

Explanation:

In the first questions , you've been provided with instantaneous velocities at two different time periods . The change in velocity within 5 secs of time is 20-10 , i.e. 10m/s

This says that a= v2-v1/t2-t1

hence acceleration would be

10/5 = 2m/s^2

Now you've acceleration , final velocity at t1 , time taken .

using the first equation of motion ,

v= u+at

10m/s = u + 2(3secs)

10 - 6 = u

u = 4m/s .

Hence option (2) is correct .

NOW LET ME GUIDE YOU THROUGH SECOND QUESTION ,

TRY DOING IT YOURSELF .

YOU'VE BEEN GIVEN THE VELOCITY AT 2 SECS.

CONSIDER IT THE INITIAL VELOCITY. THE FINAL ONE BEING 60m/s .

time difference is 2secs .

again using v=u+at you can find a .

it'd come out to be , 15m/s^2

Now acceleration is known , final velocity after 2 secs is know , and time is known .

So apply the first equation of motion again .

v=u+at

30=u+15(2)

u = 0m/s

Hence option (1) is correct.

HOPE IT HELPED YOU WELL .