Question

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Answer 1

Given :-

A bus starts from rest .

It has a accelⁿ of 0.1 m / s².

It travels for 2 minutes .

To Find :-

The speed accquired during this time .

Formula Used :-

We will use first equation of motion , which is stated as ,

$\large\qquad\qquad\boxed{\red{\bf \green{\dag} v\:\:=\:\:u\:\:+\:\:at}}$

Where ,

v is final velocity.

u is Initial velocity.

a is acceleration .

t is time taken.

Calculation :-

• Here , as per the given data ,

u = 0m/s .

t = 2min = 120 s .

a = 0.1 m / s² .

v = ? .

Now , put the value in above formula stated ,

$\tt:\implies v = u + at$

$\tt:\implies v = 0m/s + 0.1m/s^2 \times 120s$

$\tt:\implies v = \bigg\lgroup \dfrac{1}{1\cancel0}ms^{-2}\times 12\cancel0s\bigg\rgroup$

$\tt:\implies v = 0m /s +12m/s$

$\underline{\boxed{\red{\tt\longmapsto Final\: Velocity=12m/s}}}$

$\boxed{\green{\bf\pink{\dag}Hence\:the\:final\: velocity\:is\:12ms^{-1}}}$

Answer 2

Answer:

Hello,

Here's your answer:

(u) = 0

Acceleration (a) = 0.1ms-2

Time (t) = 2 minute = 120 second

(a) The speed acquired:

We know that, v = u + at

⇒ v = 0 + 0.1m/s² × 120s

⇒ v =  120m/s

Thus, the bus will acquire a speed of 120 m/s after 2 minute with the given acceleration.

b) The distance travelled:

s = ut + 1/2 at²

⇒ s = 0 × 120s + 1/2 × 0.1m/s²  × ( 120s) ²

= 1/2 × 1440m = 720m.

Thus, bus will travel a distance of 720 m in the given time of 2 minute.

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