Question

plzzzzzzzzz solve it as the speed of light​

Answer 1

Answer:

Step-by-step explanation:

LHS = √(1 + sin∅)/√(1 - sin∅)

= √(1 + sin∅) × √(1 + sin∅)/√(1 -sin∅)×√(1 +sin∅)

= √(1 + sin∅)²/√(1 -sin²∅)

= (1 + sin∅)/√cos²∅

= (1 + sin∅)/cos∅

= 1/cos∅ + sin∅/cos∅

= sec∅ + tan∅ = RHS

Answer 2

${\huge {\mathfrak {Answer :-}}}$

There goes your answer ⬇️⬇️

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⚠️ L. H. S

= sec A + tan A

= 1/cos A + sin A/cos A

= (1 + sin A) / cos A

= ${} \sqrt { (1 + sin A)^2 / cos^2 A}$

= ${} \sqrt { (1 + sin A)^2 / (1 - sin^2 A) }$

${} = \sqrt { (1 + sin A)(1 + sin A) / (1 + sin A)(1 - sin A)}$

Now, cancel (1 + sin A) from the numerator and the denominator.

${} = \sqrt { (1 + sin A) / (1 - sin A)}$

= R. H. S

Hence, Proved.

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✨HOPE THIS HELPS ✨