plzzzzzzzzzzz give me answer of my question. Very fast
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I am getting 13. check if I have made a mistake or the question is wrong.
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RAH38:
bro mera bi ye hi answer aya h
toh question mai mistake hai
kyuki method to yahi hai
m bas check karna chata ki m write hun ya ni
tum right ho
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3 (sin A−cos A)4+6(sin A+cos A)2+4(sin6A+cos6A)=3 (sin A−cos A)2 (sin A−cos A)2+6(sin2A+cos2A+2 sin A cos A)+4((sin2A)3+(cos2A)3)=3(sin2A+cos2A−2 sin A cos A)(sin2A+cos2A−2 sin A cos A)+6(1+2 sin A cos A)+4[(sin2A+cos2A)3−3sin2A cos2A(sin2A+cos2A)] (Since sin2A+cos2A=1)=3(1−2 sin A cos A)(1−2 sin A cos A)+6(1+2 sin A cos A)+4(1−3sin2A cos2A)=3(1−4 sin A cos A+4 sin2A cos2A)+6(1+2 sin A cos A)+4(1−3sin2A cos2A)=3−12 sin A cos A+12 sin2A cos2A +6+12 sin A cos A+4−12 sin2A cos2A=13 , Which is independent of A.
yaaa i too got the answer as 13
please mark my answer as branliest
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