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If a line segment is divided in A,B,C
Then ,CB is equal to is equal to ABC-BC=CB
Then ,CB is equal to is equal to ABC-BC=CB
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Hey!! that's a nice question
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We are given that XY || AC
Therefore... Ang BXY = Ang A
also, Ang BYX = Ang C ( since they are corresponding)
now, ar(ABC) / ar(XBY) = [AB/XB]^2. ..... (1)
also, ar ABC = 2 (AR XBY)
SO, ar(ABC) / ar(XBY) = 2 / 1. ...... (2)
from (1) nd (2)
[AB/XB]^2 = 2 / 1
=> AB / XB = root 2 / 1
XB / AB = 1 / root 2
1 - XB / AB = 1- 1 / root 2
AB - XB / AB is equal to root 2 - 1 / root 2
!! Thus AX / AB = 2 - ROOT 2 / 2
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hope this helps
mark as brainliest! ☺
------
We are given that XY || AC
Therefore... Ang BXY = Ang A
also, Ang BYX = Ang C ( since they are corresponding)
now, ar(ABC) / ar(XBY) = [AB/XB]^2. ..... (1)
also, ar ABC = 2 (AR XBY)
SO, ar(ABC) / ar(XBY) = 2 / 1. ...... (2)
from (1) nd (2)
[AB/XB]^2 = 2 / 1
=> AB / XB = root 2 / 1
XB / AB = 1 / root 2
1 - XB / AB = 1- 1 / root 2
AB - XB / AB is equal to root 2 - 1 / root 2
!! Thus AX / AB = 2 - ROOT 2 / 2
-----------------
hope this helps
mark as brainliest! ☺
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