Question

plzzzzzzzzzzzzz solve it

Answer 1

hey.. this is ur way of slolution....

Answer 2

Heya there !!!
Here is the answer you were looking for:
$x = 3 - 2 \sqrt{2} \\ \\ \frac{1}{x} = \frac{1}{3 - 2 \sqrt{2} }$

On rationalizing the denominator we get,

$\frac{1}{x} = \frac{1}{3 - 2 \sqrt{2} } \times \frac{3 + 2 \sqrt{2} }{3 + 2 \sqrt{2} } \\ \\ \frac{1}{x} = \frac{3 + 2 \sqrt{2} }{ {(3)}^{2} - {(2 \sqrt{2} )}^{2} } \\ \\ \frac{1}{x} = \frac{3 + 2 \sqrt{2} }{9 - 8} \\ \\ \frac{1}{x} = 3 + 2 \sqrt{2} \\ \\ \frac{1}{x} - x$

Putting the values :

$\frac{1}{x} - x = (3 + 2 \sqrt{2} ) - (3 - 2 \sqrt{2} ) \\ \\ \frac{1}{x} - x = 3 + 2 \sqrt{2} - 3 + 2 \sqrt{2} \\ \\ \frac{1}{x} - x = 4 \sqrt{2}$

Hope this helps!!!

If you have any doubt regarding to my answer, feel free to ask me in the comment section ^_^

@Mahak24

Thanks....
☺☺