Question

PM perpendicular MN, QN perpendicular MN and QN
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Answer 1

Answer:

PM+AB(given)

PN⊥AC(given)

ΔANPnadAMP

∠PNA=90∘

∠PMA=90∘

AP=AP(common)

HenceDM=PN

Answer 2

write five pairs of integers a b such that a b - 31 such per is 6 - 2 because 60 - 2 is equals to minus 3