PO and so are angle bisector of angle C B and Angle B C D respectively meet at O then prove that angle BOC = 90 -1/2 angle BAC half angle BAC
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Hello Mate!
Given : BO and CO are angle bisectors that meet at O.
To prove : < BOC = 90° - ½ < A
Proof : Please refer to attachment once.
Concept used = 1. Linear pair property.
2. Bisector angle property
3. Angle sum property.
Remember : < 1 and < PBO are equal since OB is bisector. < 2 and < QCB are equal since OC is bisector. Value of < B + < C is replaced by 180° - < A.
Have great future ahead!
Given : BO and CO are angle bisectors that meet at O.
To prove : < BOC = 90° - ½ < A
Proof : Please refer to attachment once.
Concept used = 1. Linear pair property.
2. Bisector angle property
3. Angle sum property.
Remember : < 1 and < PBO are equal since OB is bisector. < 2 and < QCB are equal since OC is bisector. Value of < B + < C is replaced by 180° - < A.
Have great future ahead!
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Thanks for the ans @ShuchiRecites
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