pocket money 10 20 30 40 number of students 4 8 12 6 find the median
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Answer:
168.3
Step-by-step explanation:
Class interval (exclusive) Class interval (inclusive) Class interval frequency Cumulative frequency
160 – 162 159.5 – 162.5 15 15
163 – 165 162.5 – 165.5 118 133 (F)
166 – 168 165.5 – 168.5 142 (f) 275
169 – 171 168.5 – 171.5 127 402
172 – 174 171.5 – 174.5 18 420
N = 420
We have
N = 420
N/2 = 420/ 2 = 120
The cumulative frequency just greater than N/2 is 275 then 165.5 – 168.5 is the median class such, that
L = 165.5, f = 142, F = 133 and h = 168.5 – 165.5 = 3
Mean = L+N2−Ff×h
= Missing close brace = 166.5 + 1.63 = 168.13
Anonymous:
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