point (2,-1), (2,4), (-2,1) and (-2,-4) are the vertices of a quadrilateral, sung distanx=ce formula, show that the quadrilateral is a rhombus
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A Rhombus is a type of Quadrilateral
So to show that a quadrilateral is a rhombus follow these steps
Consider (2,-1) point A
Consider (2,4) point B
Consider (-2,1) point C
Consider (-2,-4) point D
So the solution is
Prove that AB=BC=CD=AC BY USING DISTANCE FORMULA
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