Point (3,-1) and (6,1) lie on the line represented by the equation px+qy=9, find the values of p and q
Answers
Answered by
42
px+qy=9
p(3)+q(-1) =9
3p -q=9. -. ( 1 )
px+qy=9
p(6) +q(1) =9
6p +q=9. -(2)
subtract equation (1) from (2)
(6p+q=9)-(3p-q=9)
=9p=9
p=9/9
p=1
6p+q=9
6(1)+q=9
6+q=9
q=9-6
q=3
p(3)+q(-1) =9
3p -q=9. -. ( 1 )
px+qy=9
p(6) +q(1) =9
6p +q=9. -(2)
subtract equation (1) from (2)
(6p+q=9)-(3p-q=9)
=9p=9
p=9/9
p=1
6p+q=9
6(1)+q=9
6+q=9
q=9-6
q=3
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Answered by
15
Equation of line is px +qy = 9
Since (3,-1) lies on the line:
3p-q =9
Also (6,1) lies on the line:
6p+q =9
Solving these two equation simultaneously or by subsitution method
We get p= 2 and q = -3.
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