Question

Point (3, 4) lies on the graph of the equation 3y = kx + 7. The value of k is:​

Answer 1

$\bf\large{\underline{Question:-}}$

Point (3, 4) lies on the graph of the equation 3y = kx + 7. The value of k is

$\large\bf{\underline{Solution:-}}$

→ 3x4 = kx3 + 7 12 = 3 k+ 7

→ 12 -7 = 3k 5 = 3k

→ 5/3 = k

• Or 1.6 On putting x = 0 then y is

→ 3y = 1.6 x 0 + 7 3y = 0 +7

→ y= 7/3 y = 2.3

• On putting x = 1 then y is

→ 3y = 1.6 x1 +7 3y = 1.6 + 7

→ 3y =8.6

→ y = 8.6/3

_____________________

Answer 2

thanks for asking the question;

Answer:

k=5/3

Step-by-step explanation:

solution;

since, the equation 3y = kx + 7 lies on the point (3,4)

so, putting x=3 and y=4 we get;

3y = kx + 7

3*4=k*3+7

12=3k+7

12-7=3k

5=3k

5/3=k

therefore , the value of k is $5/3$