point a and b are on the opposite edges of a pond as shown figure find the distance between ab
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Answered by
28
By pythagores theoram hypotenuse^2=base^2+height ^2
ac^2=dc^2+ad^2
ac^2=40^2+30^2
ac^2=1600+900
ac^2=2500
ac=50
ab=ac-bc
ab=50-12
ab=38
ac^2=dc^2+ad^2
ac^2=40^2+30^2
ac^2=1600+900
ac^2=2500
ac=50
ab=ac-bc
ab=50-12
ab=38
Answered by
20
Using the Pythagoras theorem
AC = 50 m
Then AB = 50 - 12 = 38 m
AC = 50 m
Then AB = 50 - 12 = 38 m
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