Point A, B, C are collinear. If slope of line AB is
the slope of line BC.
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(i) Slope of AB=5−412−8=14=4
Slope of BC=9−528−12=416=4
Hence AB∣∣BC, but B is a point of intersect.
Hence A, B, C are collinear.
(ii) Slope of AB=3−16−6+18=−1312=−1312
Slope of BC=−10−36+6=−1312=−1312
Slope of AB= slope of BC
Hence A, B, C are collinear.
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