Math, asked by lalaneetalala, 4 months ago

Point A has coordinates (-2, 2), point
B has coordinates (0,0) and point C
has coordinates (4,0). Find the value
of angle ABC in radians.​

Answers

Answered by sundrakkannan
0

Answer:

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Answered by deepshikanagarkoti90
0

Answer:

Step-by-step explanation: if we plot the points in graph we get angle B must be obtuse angle.

 so, for finding angle B we must have slope of BA and BC which we can find from the given points .

A=(-2,2)=(x1,y1)

B=(0,0)= X2, y2

m1= y2-y1/x2-x1 = -1

similarly B= (0,0) =x1,y1

C= (4,0) = X2,y2

slope / M2 = 0 as per calculation similar to above

now,

tan(Theta) = (m1-m2)/(1+m1m2)

tan(theta) = -1

tan(theta)= - tan(45°)

tan (theta) = tan ( 180-45)

theta = 135°

1°= 2π/360 radian

135° = 3π/4 radian.

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