Prove that sinθ -cosθ+1/sinθ+ cosθ-1= tanθ-1+ secθ/tanθ+1-secθ
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Step-by-step explanation:
ANSWER
secθ(1−sinθ)(secθ+tanθ)=1
LHS.
secθ(1−sinθ)(secθ+tanθ)
=
cosθ
1
(1−sinθ)(
cosθ
1
+
cosθ
sinθ
)
=
cosθ
1
(1−sinθ)(
cosθ
1+sinθ
)
=
cos
2
θ
1−sin
2
θ
=
cos
2
θ
cos
2
θ
=1
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