point A lies in the exterior of a circle with center P and radius 8cm A tangent from A touches the circle at B If AB=15 cm Find PA
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Answer:
16.1 (approx)
Step-by-step explanation:
in triangle∆ ABP
PB=perpendicular=8cm
AB=base=15 cm
by Pythagoras theorem
AP²=AB²+BP²
AP²=15²+8²
AP²=225+64
AP²=289
AP=√289
AP=16.0934cm
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