Question

Solve the equation please
(a) 4x - 3 = 2x + 1
(b) x+8/2=4​

Answer 1

Answer:

I hope it will help you..

Answer 2

Let's solve both the equations one by one!

-----------------------------------------------------------

$\underline{ \mathfrak{\underline {Answer \: a :-}}}$

$\sf Q) \: 4x - 3 = 2x + 1$

Putting the variables and the constants on separate sides by transposing,

$\Rightarrow \sf4x - 2x = 1 + 3$

On simplifying,

$\Rightarrow \sf2x = 4$

Transposing 2 from LHS to RHS, changing it's sign,

$\Rightarrow \sf x = \dfrac{4}{2}$

Dividing 4 by 2,

$\Rightarrow\sf x = 2.$

• The value of x = 2.

-----------------------------------------------------------

$\underline{\underline{ \mathfrak{Answer \: b :-}}}$

$\sf Q) \: x + \dfrac{8}{2} = 4$

Transposing 2 from LHS to RHS, changing it's sign,

$\Rightarrow \sf x + 8 = 4 \times 2$

On simplifying,

$\Rightarrow \sf x + 8 = 8$

Transposing 8 from LHS to RHS, changing it's sign,

$\Rightarrow \sf x = 8 - 8$

On simplifying,

$\Rightarrow \sf x = 0.$

• The value of x = 0.

-----------------------------------------------------------