Math, asked by gileestephen, 10 hours ago

Point G is 10 m north of point I. Point F is 7 m west of point H, which 6 m north of point



If point M is 5 m southeast of point G and east of point H, then what is the distance between points H and M?

a) 4 m b) 5 m c) 23 m d) 3 m e) Cannot be determined ​

Answers

Answered by animish02008
3

Answer:

as distance b/w g and i is 10 m, between them, h is 6m from i... it means distance b/w h and g is 4m..

as distance b/w g and i is 10 m, between them, h is 6m from i... it means distance b/w h and g is 4m..now it is clearly visible that there is a right angled triangle (right angled at h) and distance b/w g and m is 5 m..

as distance b/w g and i is 10 m, between them, h is 6m from i... it means distance b/w h and g is 4m..now it is clearly visible that there is a right angled triangle (right angled at h) and distance b/w g and m is 5 m..using Pythagoras theorem...

as distance b/w g and i is 10 m, between them, h is 6m from i... it means distance b/w h and g is 4m..now it is clearly visible that there is a right angled triangle (right angled at h) and distance b/w g and m is 5 m..using Pythagoras theorem...4²+ (hm)² = 5²

as distance b/w g and i is 10 m, between them, h is 6m from i... it means distance b/w h and g is 4m..now it is clearly visible that there is a right angled triangle (right angled at h) and distance b/w g and m is 5 m..using Pythagoras theorem...4²+ (hm)² = 5²(hm)² = 25-16

as distance b/w g and i is 10 m, between them, h is 6m from i... it means distance b/w h and g is 4m..now it is clearly visible that there is a right angled triangle (right angled at h) and distance b/w g and m is 5 m..using Pythagoras theorem...4²+ (hm)² = 5²(hm)² = 25-16hm = 3 m

(d) 3 m

Answered by singhsahilsanskar
0

Answer:

3 is answer please make me brainslit

Similar questions