Question

Point intersection of 3x+4y=13

Answer 1

Answer:

required points are (7,-2) and (3,1)

Step-by-step explanation:

Given equation ,

3x+4y = 13

when x =7 and y = -2

Because 3×7 + 4×(-2) = 21-8 = 13

then it satisfies the given equation

when x = 3 and y = 1

then it also satisfies the given equation

Because 3×3 + 4 = 9+4 = 13

hence the points of intersection are (7,-2) , (3,1)