Question

solve simultanious equation 2x+3y=13 4x-y=-2

Answer 1

Answer:

the answer is x= .5 and y= 4

Step-by-step explanation:

( 2x + 3y = 13) x2 = 4x +6y = 26------- i

(4x-y=-2).------ ii

subtracting ii from i we get 7y=28

                                              y = 4

putting the value of y in i we get x= 0.5

Answer 2

Answer:

After solving the given simultanious equations, we get,

$x=\frac{1}{2} \\\\y=4$

Step-by-step explanation:

Given: $2x+3y=13 ,\ 4x-y=-2$

We have to solve the above simultanious equation.

We are solving in teh following way:

We have,

$2x+3y=13 ,\ 4x-y=-2$

Multiplying both sides of the equation by a

$\text { coefficient: }\left\{\begin{array}{l}2(2 x+3 y)=13 \times 2 \\4 x-y=-2\end{array}\right.$

Applying Multiplicative Distribution Law:

$\left\{\begin{array}{l}4 x+6 y=13 \times 2 \\4 x-y=-2\end{array}\right.$

Calculating the product or quotient:

$\left\{\begin{array}{l}4 x+6 y=26 \\4 x-y=-2\end{array}\right.$

Subtracting the two equations:

$4 x+6 y-(4 x-y)=26-(-2)$

$\text { Removing parentheses: } 4 x+6 y-4 x+y=26+2$

$\text { Canceling the unknown variables: } 6 y+y=26+2\\\text { Combining like terms: } 7 y=26+2\\\text { Calculating the sum or difference: } 7 y=28$

Now,

$y=\frac{28}{7} \\\\y=4$

$\text { Substituting one unknown quantity into the }\\\text { elimination: } 4 x+6 \times 4=26$

$=>4x+24=26\\=>4x=26-24\\=>4x=2\\=>x=\frac{2}{4} \\\\=>x=\frac{1}{2}$

Hence,

$x=\frac{1}{2} \\\\y=4$