Point P'(1,5)P ′ (1,5) is the image of P(-3,1)P(−3,1) under a translation.
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Step-by-step explanation:
(5,−3)
Let (x
1
,y
1
) be the image of thr point
P(3,5) with respect to the line y=x.
Then, x
1
=5,y
1
=3.
∴Q=(5,3).
Since the image of the point Q(5,3) w.r.t. the line y=0 is (a,b).
∴a=5 and b=−3.
∴(a,b)=(5,−3).
solution
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