Point P (a, 0) on the x-axis which is equidistant from points A(-1, 0) and B(5, 0). Find ‘a’.
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The point on x-axis which is equidistant from points A (-1, 0) and B(5, 0) is. ⇒12x=24⇒x=2. So, the required point is P(2, 0).
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The point on x-axis which is equidistant from points A (-1, 0) and B(5, 0) is. ⇒12x=24⇒x=2. So, the required point is P(2, 0).
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