Question

point p has coordinates (-4, -2) and point Q has coordinates (4,3) calculate the shortest distance between p and q

Answer 1

Answer:

shortest distance between p and q is  $\sqrt{89}$

Step-by-step explanation:

coordinates of points 'p' and 'q' are given as :

p(-4 , -2)

q(4,3)

the shortest distance between p and q can be found by using distance formula.

distance formula = $\sqrt{(a-x)^2 + (b - y)^2}$

where (a, b) and (x, y) can be  given points

substitute values of  

a = -4 , b = -2 , x = 4 and y = 3

distance = $\sqrt{(-4-4)^2 + (-2-3)^2}$

=$\sqrt{(-8)^2 + (-5)^2}$

(-8)² = (-8)(-8) = (8)(8) = 64

(-5)² = (-5)(-5) = (5)(5) = 25

where (-)(-) = (+)

substitute the values:

$\sqrt{(-8)^2 + (-5)^2}$  = $\sqrt{64 + 25}$

= $\sqrt{89}$

shortest distance between p and q is  $\sqrt{89}$

Answer 2

Answer:

9.4

:)

the top answer says $\sqrt{89}$ which isnt wrong it's just not simplified, it simplifies to 9.434, but to 1dp its 9.4