Question

point p is midpoint of seg AB. If Ap = X + 3 . find l ( PB ) and ( AB )

Answer 1

Since P is mid point of segment AB then P divedes AB in equal lengths.

1. Given length of Ap is X+3 hence length of PB will also be X+3
2. length of Ap+pB=length of AB
3. hence AB=X+3+X+3=2X+6

I think this will help u.If not please comment

Answer 2

I(PB) = X + 3 , I(AB) = 2X + 6

Correct question : The point P is midpoint of seg AB. If I(AP) = X + 3 , find I(PB) , I(AB)

Given :

• The point P is midpoint of seg AB.

• I(AP) = X + 3

To find :

I(PB) , I(AB)

Solution :

Step 1 of 2 :

Write down the given data

Here it is given that , the point P is midpoint of seg AB.

I(AP) = X + 3

Step 2 of 2 :

Find I(PB) , I(AB)

Since P is midpoint of seg AB

∴ I(AP) = I(PB)

⇒ I(PB) = X + 3

Again ,

I(AB) = I(AP) + I(PB)

⇒ I(AB) = X + 3 + X + 3

⇒ I(AB) = 2X + 6

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