Question

Point P lies in the exterior of a circle with centre O. Tangents through P touch the circle at A and B. If the angle formed by PA and PB is of 80°, then angle POA = ?​

Answer 1

Answer:

Step-by-step explanation:here AOBP is a cyclic qadrilateral

and we know that the sum of opposite angles of a cyclic

quadrilateral is 180 so angle AOB+angleAPB=180

                                       angle AOB+80=180

                                       angleAOB=180-80

                                        angle AOB=100

join PO , PO bisects angle AOB and angle APB

Hence angle POA=100/2

            angle POA=50